Object - SerializeJson

A T extension method that serialize an object to Json.

Try it

public static void Main()
{
	var obj = new List<string> {"Fizz", "Buzz"};

	//C# Extension Method: Object - SerializeJson	
    string result =obj.SerializeJson();
	var result2 = result.DeserializeJson<List<string>>();
    Console.WriteLine( result2[0]);
    Console.WriteLine(result2[1]);
}

View Source
using System.IO;
using System.Runtime.Serialization.Json;
using System.Text;

public static partial class Extensions
{
    /// <summary>
    ///     A T extension method that serialize an object to Json.
    /// </summary>
    /// <typeparam name="T">Generic type parameter.</typeparam>
    /// <param name="this">The @this to act on.</param>
    /// <returns>The Json string.</returns>
    public static string SerializeJson<T>(this T @this)
    {
        var serializer = new DataContractJsonSerializer(typeof (T));

        using (var memoryStream = new MemoryStream())
        {
            serializer.WriteObject(memoryStream, @this);
            return Encoding.Default.GetString(memoryStream.ToArray());
        }
    }

    /// <summary>
    ///     A T extension method that serialize an object to Json.
    /// </summary>
    /// <typeparam name="T">Generic type parameter.</typeparam>
    /// <param name="this">The @this to act on.</param>
    /// <param name="encoding">The encoding.</param>
    /// <returns>The Json string.</returns>
    public static string SerializeJson<T>(this T @this, Encoding encoding)
    {
        var serializer = new DataContractJsonSerializer(typeof (T));

        using (var memoryStream = new MemoryStream())
        {
            serializer.WriteObject(memoryStream, @this);
            return encoding.GetString(memoryStream.ToArray());
        }
    }
}